LeetCode 每日一题：824. 山羊拉丁文

824. 山羊拉丁文

简单模拟，强调对函数isalpha和tolower等字符处理函数的运用

// shiran
#include <bits/stdc++.h>
using namespace std;

#define rep(i, a, n) for (int i = a; i < n; i++)
#define per(i, n, a) for (int i = n - 1; i >= a; i--)
#define sz(x) (int)size(x)
#define fi first
#define se second
#define all(x) x.begin(), x.end()
#define pb push_back
typedef long long ll;
typedef pair<int, int> PII;
const int mod = 1000000007;

class Solution
{
    
public:
    set<char> S = {
    'a', 'e', 'i', 'o', 'u'};
    string toGoatLatin(string s)
    {
    
        string res, post = "a";
        rep(i, 0, sz(s))
        {
    
            int j = i;
            while (j < sz(s) && isalpha(s[j]))
                j++;
            if (S.count(tolower(s[i])))
            {
    
                res += s.substr(i, j - i) + "ma" + post;
            }
            else
            {
    
                res += s.substr(i + 1, j - i - 1) + s[i] + "ma" + post;
            }
            post += "a";
            i = j;
            if (i == sz(s)) continue;
            res += " ";
        }
        return res;
    }
};