OJ daily practice - grade score

Problem description ：

Give a 100 point mark , Output grade is required ‘A’、‘B’、‘C’、‘D’、‘E’.
90 Points and above are A
80-89 It is divided into B
70-79 It is divided into C
60-69 It is divided into D
60 It is divided into the following E

Input
An integer 0－100 within , Represents the achievement of the hundred mark system

Output
A character , Indicates the grade

Examples

Input
90

Output
A

Java Code ：

import java.util.Scanner;

public  class Main {
    
    public static void main(String[] args) {
    

        Scanner rd=new Scanner(System.in);

        int a=rd.nextInt();

        String b=check(a);


// System.out.println(b);

    }


    public  static String check(int a){
    

        if(a>=90){
    
            System.out.println("A");
        }else if(a>=80&&a<=89){
    
            System.out.println("B");
        }else if(a>=70&&a<=79){
    
            System.out.println("C");
        }else if(a>=60&&a<=69){
    
            System.out.println("D");
        }else{
    
            System.out.println("E");
        }
        return null;
    }
}

C Code ：

#include <stdio.h>
int main(){
    
    int score;
    scanf("%d",&score);
    if(score>=90){
    
        printf("A");
    }else if(score>=80&&score<=89){
    
        printf("B");
    }else if(score>=70&&score<=79){
    
        printf("C");
    }else if(score>=60&&score<=69){
    
        printf("D");
    }else{
    
        printf("E");
    }
}

python Code ：

score=int(input())
if score>=90 :
    print("A")
elif score>=80 and score<=89:
    print("B")
elif score>=70 and score<=79:
    print("C")
elif score>=60 and score<=69:
    print("D")
elif score<60:
    print("E")

author ：KJ.JK
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