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790. The cube root of a number

2022-08-05 12:01:00 【aJupyter】

Article table of contents

Question
Ideas
Code

Question

Given a floating-point number n, find its cubic root.

Input format
One line contains a floating-point number n.

Output format
One line, including a floating point number, represents the solution of the problem.

Note that the result is rounded to 6 decimal places.

Data Range
−10000≤n≤10000
Input Sample:
1000.00
Output Sample:
10.000000

Ideas

Real bisection

Code

n = float(input())l,r = -100,100while (r-l) > 1e-8: # Keep x decimal places and write 1e-(x+2) here# Do not use bitwise operations to divide real numbers: bitwise operations are integer divisionsmid = (l + r) / 2if mid**3 >= n:r = midelse:l = midprint('{:.6f}'.format(l))