Difficulty: Easy

Given an integer n, please return a string of n characters, where each character occurs exactly an odd number of times in the string.

The returned string must contain only lowercase English letters.If there are multiple strings that meet the requirements of the question, any one of them can be returned.

Example 1:

Input: n = 4
Output: "pppz"
Explanation: "pppz" is a, since 'p' occurs 3 times and 'z' occurs 1 time.Of course, there are many other strings that also meet the title requirements, such as: "ohhh" and "love".

Example 2:

Input: n = 2
Output: "xy"
Explanation: "xy" is a, because 'x' and 'y' each occur 1 time.Of course, there are many other strings that also meet the requirements of the title, such as: "ag" and "ur".

Example 3:

Enter:n = 7Output:"holasss"

Tip:

• 1 <= n <= 500

Solution:

class Solution:def generateTheString(self, n: int) -> str:if n == 1:return 'a'else:if n%2 ==0:return 'a'*(n-1) + 'b'else:return 'a'*(n)