Return value of unique function of STL

unique: Keep only one copy of objects with continuous same values , from s And e Iterator to specify the processing range , And returns the iterator at the end of the compressed sequence

#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
int main()
{
    
 const int size = 10;
 int a[size] = {
     54,10,10,33,33,54,54,36,54,10};
 vector <int> v(a, a + size);
 vector <int>::iterator start, end, it, pos;
 start = v.begin();
 end = v.end();
 pos = unique(start, end);
 cout << *pos;
 cout << endl;
 for (it = start; it != pos; it++)
  cout << *it<<" ";
  return 0;
  }

Execution results ：36
54 10 33 54 36 54 10
unique The return iterator points to 36
36 It's confusing , Isn't it pointing to the end of the sequence ？10 Next
Now print the complete vector, give the result as follows

#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
int main()
{
    
 const int size = 10;
 int a[size] = {
     54,10,10,33,33,54,54,36,54,10};
 vector <int> v(a, a + size);
 vector <int>::iterator start, end, it, pos;
 start = v.begin();
 end = v.end();
 pos = unique(start, end);
 cout << *pos;
 cout << endl;
 for (it = start; it != end; it++)
  cout << *it<<" ";
 return 0;
}

36
54 10 33 54 36 54 10 36 54 10
thus it can be seen ,pos It does point to the next... At the end of the sequence ,unique Move non repeating elements to the front , The remaining elements remain in their original positions