Python exploit for vsftpd 2.3.4 - Backdoor Command Execution

Overview

CVE-2011-2523 - vsftpd 2.3.4 Exploit

Discription

  • vsftpd, which stands for Very Secure FTP Daemon,is an FTP server for Unix-like systems, including Linux. It is licensed under the GNU General Public License. It supports IPv6 and SSL.

  • In July 2011, it was discovered that vsftpd version 2.3.4 downloadable from the master site had been compromised. Users logging into a compromised vsftpd-2.3.4 server may issue a :) smileyface as the username and gain a command shell on port 6200. This was not an issue of a security hole in vsftpd, instead, someone had uploaded a different version of vsftpd which contained a backdoor. Since then, the site was moved to Google App Engine.

Requirements

sudo apt update
sudo apt install python3
sudo apt install python3-pip
pip install argparse

Installation

git clone https://github.com/padsalatushal/CVE-2011-2523.git
cd ./CVE-2011-2523
chmod +x exploit.py

Usage

python3 exploit.py -host Target_IP

Example : python3 exploit.py -host 192.168.168.128

image

Test

You can test the exploit on Metasploitable2

Resources

https://www.computersecuritystudent.com/SECURITY_TOOLS/METASPLOITABLE/EXPLOIT/lesson8/index.html https://subscription.packtpub.com/book/networking_and_servers/9781786463166/1/ch01lvl1sec18/vulnerability-analysis-of-vsftpd-2-3-4-backdoor

Owner
Padsala Tushal
Arduino,Python,Shell,Batch
Padsala Tushal
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