[programming question] water bottle

Regulations of a store ： Three empty water bottles can be replaced by one soda , Allow to borrow an empty soda bottle from the boss （ But it must be returned ）.

Xiao Zhang has n Empty water bottle , She wants to know how many bottles of soda she can drink at most .

Data range ： The positive integer entered satisfies  

Be careful ： There are multiple sets of inputs for this question . Input 0 End of input , You don't have to output the results .

Input description :

The input file contains at most 10 Group test data , One line per data , Contains only a positive integer n（ 1<=n<=100 ）, Indicates the number of empty water bottles on the small hand .n=0 End of input , Your program should not deal with this line .

Output description :

For each group of test data , Output one line , Indicates the maximum number of soda bottles to drink . If you can't drink a bottle , Output 0.

Input example 1:

3
10
81
0

Output example 1:

1
5
40

Example illustrate 1:

 Examples  1  explain ： Exchange three empty bottles for a bottle of soda , There is one empty bottle left, and the exchange cannot continue 
 Examples  2  explain ： Trade nine empty bottles for three bottles of soda , There are four empty bottles left, and then three empty bottles for a bottle of soda , There are two empty bottles left , Borrow an empty bottle from the boss and then exchange three empty bottles for a bottle of soda. After drinking, one empty bottle will be returned to the boss   

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        //  Answer key 
        // 1.  Borrow one empty bottle for every two empty bottles ;
        // 2.  Three empty bottles   in   A soda ;
        // 3.  Return a borrowed empty bottle .
        Scanner sc = new Scanner(System.in);
        while(true) {
            int num  = sc.nextInt();
            if(num == 0) {
                return;
            }
            System.out.println(num / 2);
        }
    }
}

#include <cstdio>
using namespace std;
int main() {
    int n;
    while(true) {
        scanf("%d", &n);
        if(n == 0) {
            break;
        }
        printf("%d\n", n / 2);
    }
    return 0;
}

while True:
    n = int(input())
    if n == 0:
        break
    print(n // 2)