1 Background

Enter m n , linked list, and get a linked list with starting point m and ending point n

2 Problem-solving ideas

1) First, get N nodes according to the input n, see this article for details

https://blog.csdn.net/an13654067079/article/details/126173743

2) m node, n node m node as the head of the new linked list

3) The previous node of the m node mPre.next = null

The next node of n nodes nNext.next = null

The new linked list is intercepted, the problem is not difficult

 public static void main(String[] args) {ListNode listNode = ListNodeUtil.getListNode();int m = 2;int n = 4;//Get m nodes, n nodesListNode mNode = index(listNode, m);ListNode nNode = index(listNode, n);if(m!=1){//Get the previous node of mint mPre = m-1;ListNode mPreNode = index(listNode, mPre);mPreNode.next = null;}ListNode nNextNode = nNode.next;nNode.next = null;System.out.println(mNode);}/*** Get the node at the specified location** @param listNode* @param index* @return*/public static ListNode index(ListNode listNode , int index){ListNode dummyNode = new ListNode();dummyNode.setVal(0);dummyNode.setNext(listNode);int n = 1;for(int i = 0 ; i< index; i++){dummyNode = dummyNode.getNext();}return dummyNode;}

import lombok.Data;@Datapublic class ListNode {/*** current node value*/public int val;/*** next node*/public ListNode next ;}

public class ListNodeUtil {/*** Get the linked list** @return*/public static ListNode getListNode(){ListNode one = new ListNode();one.setVal(1);ListNode two = new ListNode();two.setVal(2);ListNode three = new ListNode();three.setVal(3);ListNode four = new ListNode();four.setVal(4);ListNode five = new ListNode();five.setVal(5);one.setNext(two);two.setNext(three);three.setNext(four);four.setNext(five);return one;}}