Assembly Language Learning (6) Curriculum Design 1

This part is divided into the first10Course design of part of the chapter after.

The main task is to experiment in sevenPower ideaCompany's data according to below format displayed on the screen.

实验思路：

1.The main body of the code is a traversal21行的循环.

2.对于每行,The most important job is to将dataPart of the value is copied to theMemory location can be displayed on the screen.

Set the register,data段部分,Segment address withds寄存器,偏移地址用bp和si寄存器.

The screen part,Segment address withes寄存器,偏移地址用di寄存器.

Note that at the beginning of each row,需要重新给di赋值,每行结束后,需要对es、bp、si进行处理.

3.For each row to replicate data,首先将Vintage copy过来,之后通过调用函数Conversion and copy the rest of the data.

4.编写子程序用于转化数据：

Call before writing spill-resistant function,反复除以10后加30h入栈,Then the stack deposited in the corresponding position memory.

5.一定不能忘记,Every word of two word unit,The first word JieCunASCII码,The second word JieCun properties.

出现过的问题：

1.似乎使用[bp]默认的是ss:[bp],所以最好加上ds:[bp].

2.按理说应该是从B8000hMemory can show,但是The actual experimentB8168h都显示不出来.Didn't know what went wrong,调试了很久……Now guess may be to press the enter key when debugging,Lead to back up a few lines.

3.The other register is less,所以需要The use of planning in advance register.

代码为：

assume cs:code,ds:data,ss:stack
data segment
   year    db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
           db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
           db '1993','1994','1995'
   income  dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
           dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000

   employeenum dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
               dw 11542,14430,15257,17800
data ends

stack segment
        db 64 dup (0)
stack ends

code segment
start:      mov ax,data
            mov ds,ax
            mov ax,stack
            mov ss,ax
            mov sp,64
            mov ax,0B82Ah
            mov es,ax
            mov bl,7
            mov bp,0
            mov si,0

            mov cx,21
l:          mov di,8
            push cx

            mov cx,4
l1:         mov ah,ds:[bp]
            mov es:[di],ah
            mov es:[di+1],bl
            add bp,1
            add di,2
            loop l1                     

            pop cx
            mov di,8
            sub bp,4

            mov dx,ds:[bp+86]
            mov ax,ds:[bp+84]
            add di,20
            call dtoc

            mov dx,0
            mov ax,ds:[si+168]
            add di,20
            call dtoc

            mov dx,ds:[bp+86]
            mov ax,ds:[bp+84]
            div WORD ptr ds:[si+168]
            mov dx,0
            add di,20
            call dtoc

            mov ax,es
            add ax,0Ah
            mov es,ax
            add bp,4
            add si,2
            loop l

            mov ax,4C00h
            int 21h

dtoc:       push cx
            push si
            mov si,di
            mov cx,0                ;提前放入0,Confirmation that the stack is empty
            push cx
s:          mov cx,10
            call divdw
            add cx,30h
            push cx
            mov cx,ax
            add cx,dx
            jcxz s1
            jmp short s

s1:         pop cx
            jcxz ok
            mov es:[si],cl
            mov es:[si+1],bl
            add si,2
            jmp short s1

ok:         pop si
            pop cx
            ret

divdw:      push bx
            push si
            mov bx,ax      
            mov ax,dx
            mov dx,0       
            div cx        
            mov si,ax
            mov ax,bx       
            div cx          
            mov cx,dx
            mov dx,si 
            pop si
            pop bx
            ret 
code ends
end start

实验结果：

Or filled with a sense of accomplishmentヾ(@゜∇゜@)ノ