es6 How to find the intersection of two arrays

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Implementation method ：1、 Use “new Set( Array )” Statement converts both arrays to set Collection types ;2、 Use “new Set([... aggregate 1].filter(x => aggregate 2.has(x)))” Statement to get the intersection of two sets , A new set containing all intersection elements will be returned .

The operating environment of this tutorial ：windows7 System 、ECMAScript 6 edition 、Dell G3 The computer .

stay es6 in , You can use set Object's has() Method with the array of filter() To find the intersection of two arrays .

• Set yes ES6 New data structure , It's like an array , But there are no duplicate values in itself . Take advantage of this feature , We can turn the array into Set Type for de duplication , And then use Array.from Method to convert it into an array .

• Set has() Method instructions Set Whether the object contains the specified value . If the specified value exists , Then return to true , Otherwise return false .

let a=[1, 2, 3];let b=[3, 5, 2];newA = new Set(a);newB = new Set(b); let intersectionSet = new Set([...newA].filter(x => newB.has(x)));console.log(intersectionSet);

And you can see that at this point , Intersection elements are contained in a set Returns... In the collection , available Array.from Method to convert a collection to an array type

• Array.from Method to convert two types of objects into real arrays ： Array like objects （array-like object） Ergodic （iterable） The object of （ Include ES6 New data structure Set and Map）.
  

let intersectionSet = Array.from(new Set([...newA].filter(x => newB.has(x))));console.log(intersectionSet);

Expanding knowledge ： Union ／ Difference set

let a = new Set([1, 2, 3]);let b = new Set([3, 5, 2]); //  Combine let unionSet = new Set([...a, ...b]);//[1,2,3,5]// ab Difference set let differenceABSet = new Set([...a].filter(x => !b.has(x)));

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