OJ daily practice - Bonus

Problem description ：

The bonus paid by the enterprise is based on the profit （I） Royalty .
The profit is no higher than 100000 yuan , Bonus can be raised 10% The profits of the ;
Profit exceeds 100000 element , But not higher than 200000 Yuan time ,100000 The part of RMB yuan and below shall be according to 10％ Royalty , exceed 100000 Part of the yuan , It's a percentage 7.5%;
Profit exceeds 200000 element , But not higher than 400000 Yuan time ,200000 The part of RMB yuan and below shall be according to 10％ Royalty , exceed 200000 Part of yuan by 5％ Royalty ;
Profit exceeds 400000 element , But not higher than 600000 Yuan time ,400000 The part of RMB yuan and below shall be according to 10％ Royalty , exceed 400000 Part of yuan by 3％ Royalty ;
Profit exceeds 600000 element , But not higher than 1000000 Yuan time ,600000 The part of RMB yuan and below shall be according to 10％ Royalty , exceed 600000 Part of yuan by 1.5% Royalty ;
Profit exceeds 1000000 element ,1000000 The part of RMB yuan and below shall be according to 10％ Royalty , exceed 1000000 Part of yuan by 1% Royalty .

Input
A positive integer , Represents the profit of the current month .

Output
A floating point number , Indicates the bonus of the current month , Accurate to the decimal point 1 position .

Examples

Input
900
Output
90.0

Java Code ：

import java.util.*;
public class Main{
    
	public static void main(String[] args) {
    
		Scanner rd= new Scanner(System.in);	
		double j=0;
		int a=rd.nextInt();
		if(a<100000) {
    
			j=a*0.1;
			System.out.println(j);
		}else if(a>100000&&a<=200000) {
    
			j=100000*0.1+(a-100000)*0.075;
			System.out.println(j);
		}else if(a>200000&&a<=400000) {
    
			j=200000*0.1+(a-200000)*0.05;
			System.out.println(j);
		}else if(a>400000&&a<=600000) {
    
			j=400000*0.1+(a-400000)*0.03;
			System.out.println(j);
		}else if(a>600000&&a<=1000000) {
    
			j=600000*0.1+(a-600000)*0.015;
			System.out.println(j);
		}else {
    
			j=1000000*0.1+(a-1000000)*0.01;
			System.out.println(j);
		}
	}
}

C Code ：

#include <stdio.h>
int main(){
    
		double j=0;
		int a;
        scanf("%d",&a);
		if(a<100000) {
    
			j=a*0.1;
			printf("%.1f",j);
		}else if(a>100000&&a<=200000) {
    
			j=100000*0.1+(a-100000)*0.075;
			printf("%.1f",j);
		}else if(a>200000&&a<=400000) {
    
			j=200000*0.1+(a-200000)*0.05;
			printf("%.1f",j);
		}else if(a>400000&&a<=600000) {
    
			j=400000*0.1+(a-400000)*0.03;
			printf("%.1f",j);
		}else if(a>600000&&a<=1000000) {
    
			j=600000*0.1+(a-600000)*0.015;
			printf("%.1f",j);
		}else {
    
			j=1000000*0.1+(a-1000000)*0.01;
			printf("%.1f",j);
		}
	}

author ：KJ.JK
This article is only for communication learning , Without the permission of the author , Prohibited reproduced , Let alone for other purposes , Offenders will investigate .
If the article is helpful to you , Welcome to praise or star, Your support is the greatest encouragement to the author , The shortcomings can be corrected in the comments section , Communication and learning