Rearranging log files for leetcode simple question

subject

Give you a log array logs. Each log is a space separated string , The first word is a mixture of letters and numbers identifier .
There are two different types of logs ：
Alphabet log ： Except identifier , All words consist of lowercase letters
Digital log ： Except identifier , All words consist of numbers
Please reorder the logs according to the following rules ：
all Alphabet log All in line Digital log Before .
Alphabet log When the content is different , After ignoring the identifier , Sort the contents alphabetically ; When the content is the same , Sort by identifier .
Digital log The original relative order should be retained .
Return the final order of logs .
Example 1：
Input ：logs = [“dig1 8 1 5 1”,“let1 art can”,“dig2 3 6”,“let2 own kit dig”,“let3 art zero”]
Output ：[“let1 art can”,“let3 art zero”,“let2 own kit dig”,“dig1 8 1 5 1”,“dig2 3 6”]
explain ：
The contents of the alphabetic log are different , So the order is “art can”, “art zero”, “own kit dig” .
The digital log retains the original relative order “dig1 8 1 5 1”, “dig2 3 6” .
Example 2：
Input ：logs = [“a1 9 2 3 1”,“g1 act car”,“zo4 4 7”,“ab1 off key dog”,“a8 act zoo”]
Output ：[“g1 act car”,“a8 act zoo”,“ab1 off key dog”,“a1 9 2 3 1”,“zo4 4 7”]
Tips ：
1 <= logs.length <= 100
3 <= logs[i].length <= 100
logs[i] in , Between words Single The blank space to separate
Topic data assurance logs[i] Each has an identifier , And there is at least one word after the identifier
source ： Power button （LeetCode）

Their thinking

   This question needs to rewrite the sorting information according to the conditions , If the first space in each element is followed by a number, it is concluded that this is a digital log , Otherwise, it's the letter log , So we just need to look at the first character after the first space of a single element . because python Self contained sort The default function is stable sorting , Therefore, when arranging the digital log, it is good to directly assign a value of the same size , The rest of the rules can use tuples to separate the first and second order .

class Solution:
    def reorderLogFiles(self, logs: List[str]) -> List[str]:
        def sort_rule(x):
            index=x.index(' ')
            if x[index+1].isdigit():
                return 'z'*100,'z'*100
            else:
                return x[index+1:],x[0:index]
        return sorted(logs,key=sort_rule)