PAT Level B-B1028 Census (20)

A town conducts a census and gets the birthdays of all its residents.Now please write a program to find the oldest and youngest people in town.

This ensures that each date entered is legal, but not necessarily reasonable - assuming it is known that there are no people over 200 in town, and today is September 6, 2014, so people over 200Birthdays and unborn birthdays are both unreasonable and should be filtered out.

input format:

The input gives a positive integer N in the first line, the value is (0,105]; the next N lines, each line gives the name of 1 person (a string consisting of no more than 5 English letters), and press yyyy/mm/dd (ie year/month/day) format. The title ensures that the oldest and youngest people are not tied.

Output format:

Sequentially print the number of valid birthdays, the names of the oldest and youngest on a single line, separated by spaces.

Input sample:

5John 2001/05/12Tom 1814/09/06Ann 2121/01/30James 1814/09/05Steve 11/20/1967

Example output:

3 Tom John

Test point 3: No valid birthday, special judgment output

#include#include#includeusing namespace std;#define year 2014#define month 9#define day 6//Test point 3: no valid birthday, special judgment output//young and old record the youngest and oldest peoplestruct person{string name;int yy,mm,dd;}young = {"", year - 201, month , day}, old ={"", year + 1, month, day};vector table;int main(){int n;cin >> n;for(int i = 0; i < n; ++i){int y,m,d;string name;cin >> name;scanf("%d/%d/%d", &y,&m,&d);//It is possible that the year or month or day of birth exceeds today's dateif(y > year || (y == year && m > month) || (y == year && m == month && d > day)) continue;// It is possible that the year or month or day of birth is over 200 years oldelse if(y < year - 200 || (y == year -200 && m < month) || (y == year - 200 && m == month && d < day)) continue;table.push_back({name, y, m, d});//Year or month or day can be used as a younger judgmentif(y > young.yy || (y == young.yy && m > young.mm) ||(y == young.yy && m == young.mm && d > young.dd))young = {name, y, m, d};//year or month or day can be used as an older judgmentif(y < old.yy || (y == old.yy && m < old.mm) || (y == old.yy && m == old.mm && d < old.dd))old ={name, y, m, d};}//Test point 3, no valid birthday, special sentenceif(table.size() == 0){cout << table.size()<