Vowel substring in statistical string of leetcode simple problem

subject

Substring Is a continuous... In a string （ Non empty ） The character sequence of .
Vowel substring yes only By vowels （‘a’、‘e’、‘i’、‘o’ and ‘u’） A substring composed of , And it must contain All five vowel .
Give you a string word , Count and return word in Number of vowel substrings .
Example 1：
Input ：word = “aeiouu”
Output ：2
explain ： The following is a list word Vowel substring in （ Bold part in italics ）：

• “aeiouu”
• “aeiouu”
  Example 2：

Input ：word = “unicornarihan”
Output ：0
explain ：word Does not include 5 Kinds of vowels , So there will be no vowel substring .
Example 3：
Input ：word = “cuaieuouac”
Output ：7
explain ： The following is a list word Vowel substring in （ Bold part in italics ）：

• “cuaieuouac”
• “cuaieuouac”
• “cuaieuouac”
• “cuaieuouac”
• “cuaieuouac”
• “cuaieuouac”
• “cuaieuouac”
  Example 4：
  Input ：word = “bbaeixoubb”
  Output ：0
  explain ： All substrings containing all five vowels contain consonants , So there is no vowel substring .
  Tips ：
  1 <= word.length <= 100
  word It's only made up of lowercase letters
  source ： Power button （LeetCode）

Their thinking

   Traversal string , Enumerate from the current string to the right , If you can meet non repeated or repeated vowels all the way, and the type can reach 5 It's a string , If you break halfway, you will not jump out of the current enumeration directly , Proceed to the next enumeration , Start with the next character of the current character .

class Solution:
    def countVowelSubstrings(self, word: str) -> int:
        count,alpha=0,{
    'a','e','i','o','u'}
        for i in range(len(word)):
            if word[i] in alpha:
                temp={
    word[i]}
            else:
                continue
            for j in range(i+1,len(word)):
                if word[j] in alpha:
                    temp.add(word[j])
                else:
                    break
                if len(temp)==5:
                    count+=1
        return count