3342: String manipulation problem solving

原题

看到 CSDN The solution to this question is rather lengthy,The simplified code is given here,

这道题是一道不错的 string class function exercises,There are many details to pay attention to

AC code:

#include <iostream>
#include <string>
#include <cstdlib>
#include <sstream>
using namespace std;
#define a_i atoi(get().c_str())

string a[25],get();int n=0;

inline string add(){
    
    string s1=get(),s2=get();
    if(s1.size()>5||s2.size()>5)return s1+s2;
    int a1=atoi(s1.c_str()),a2=atoi(s2.c_str());
    string s3=to_string(a1),s4=to_string(a2);
    if(s1==s3&&s2==s4)return to_string(a1+a2);
    return s1+s2;
}

inline string copy(){
    int x=a_i,pos=a_i,len=a_i;return a[x].substr(pos,len);}

inline string find(){
    
    string s=get();int x=a_i;
    return a[x].find(s)==string::npos?to_string((int)s.length()):to_string(a[x].find(s));
}

inline string rfind(){
    
    string s=get();int x=a_i;
    return a[x].rfind(s)==string::npos?to_string((int)s.length()):to_string(a[x].rfind(s));
}

inline void insert(){
    string s=get();a[a_i].insert(a_i,s);}

inline void reset(){
    string s=get();a[a_i]=s;}

inline void print(){
    cout<<a[a_i]<<'\n';}

inline void printall(){
    for(int i=1;i<=n;i++)cout<<a[i]<<'\n';}

inline string get(){
    
    string s;cin>>s;
    if(s=="add")return add();
    else if(s=="copy")return copy();
    else if(s=="find")return find();
    else if(s=="rfind")return rfind();
    else if(s=="insert")insert();
    else if(s=="reset")reset();
    else if(s=="print")print();
    else if(s=="printall")printall();
    else return s;return "";
}

signed main(){
    
    cin>>n;for(int i=1;i<=n;i++)cin>>a[i];
    while(get()!="over");
    return 0;
}