当前位置:网站首页>每日sql-员工奖金过滤和回答率排序第一
每日sql-员工奖金过滤和回答率排序第一
2022-08-11 05:36:00 【吃再多糖也不长胖】
每日sql 1-员工奖金
求出奖金少于1000的员工名字和奖金
DDL
Create table If Not Exists Employee (EmpId int, Name varchar(255), Supervisor int, Salary int);Create table If Not Exists Bonus (EmpId int, Bonus int);insert into Employee (EmpId, Name, Supervisor, Salary) values (3, 'Brad', null, 4000);insert into Employee (EmpId, Name, Supervisor, Salary) values (1, 'John', 3, 1000);insert into Employee (EmpId, Name, Supervisor, Salary) values (2, 'Dan', 3, 2000);insert into Employee (EmpId, Name, Supervisor, Salary) values (4, 'Thomas', 3, 4000);insert into Bonus (EmpId, Bonus) values (2, 500);insert into Bonus (EmpId, Bonus) values (4, 2000);
sql
select Employee.Name,Bonus.Bonus FROM Employee join Bonus on Employee.EmpId=Bonus.EmpId where Bonus.Bonus <1000 or Bonus.Bonus is null;
2-求出回答率最高的问题
一张表记录着每个问题的展示show和回答answer状态,如果没回答则用skip代替answer状态。求回答率最高的问题
DDL
Create table If Not Exists survey_log (uid int, action varchar(255), question_id int, answer_id int, q_num int, timestamp int);insert into survey_log (uid, action, question_id, answer_id, q_num, timestamp) values (5, 'show', 285, null, 1, 123);insert into survey_log (uid, action, question_id, answer_id, q_num, timestamp) values (5, 'answer', 285, 124124, 1, '124');insert into survey_log (uid, action, question_id, answer_id, q_num, timestamp) values (5, 'show', 369, null, 2, 125);insert into survey_log (uid, action, question_id, answer_id, q_num, timestamp) values (5, 'skip', 369, null, 2, 126);
sql
select question_id
from survey_log
group by question_id
order by sum(case when action ="answer" then 1 else 0 end )/sum(case when action = "show" then 1 else 0 end) desc limit 1;
边栏推荐
猜你喜欢
随机推荐
uboot sets the default bootdelay
类的定义、类的继承以及super的使用
SECURITY DAY05 (Kali system, scanning and caught, SSH basic protection, service SECURITY)
numpy和tensor增加或删除一个维度
从mask-rcnn到shp
抖音分享口令url API工具
【LeetCode】2034. 股票价格波动(思路+题解)双map
Sturges规则
HCIP MGRE\OSPF Comprehensive Experiment
训练分类器
一个小时快速熟悉MySQL基本用法
xx is not recognized as internal or external command
【LeetCode】851.喧闹与富有(思路+题解)
OA项目之我的审批(查询&会议签字)
八股文之redis
损失函数——交叉熵
cloudreve使用体验
华为防火墙-5-NAT
TOP2两数相加
pytorch下tensorboard可视化深坑