Hcip fifth experiment

Job requirements

Homework results

After the subnet is divided into

polymeric 172.16.192.0/19 and 172.16.224.0/19 Network segment is not a waste , It can be used as a backup network segment

notes ： Generally, the user network segment mask is divided into 24、25、26 That's it. If you divide it again （ for example 23） There is a possibility of saturation , The Internet will be very catchy

First pair a0 To operate ,ip Set the default after configuration

  Due to repeated operation , Show only r3

build mgre

Central site r3 To configure

  Enable pseudo broadcast

mgre Configuration of branches

Due to repeated configuration , Show only r5

 OSPF To configure

r1,r2 Because in a1, So you can declare all interfaces directly

 r3 Because an interface is in a1, In a a0, So we should declare separately

r3 Need to be in a1 Declared ip yes 172.16.33.3/29 and 172.16.36.1/24 , After transformation, it becomes 172.16.00100001 and 172.16.00100100 , The last three are different , So the anti mask should be 00000111, It means that the last three can change

r3 stay a1 The order announced is --- network 172.16.32.0 0.0.7.255

r5 stay a0, Direct one-time announcement network 172.16.0.0 0.0.255.255

r6 Need to be in a0 Declare l0 （172.16.3.1/24） and t0（172.16.1.3/29） Interface

  stay a2 Just declare the interface directly

The rest of the routers operate as above