Freecodecamp ---- budget & category exercise

1 The analysis of the topic is as follows

1.1 category class

Ask for in category class Four or five functions are defined in ：

• deposit(amount, description=''), The following format is added ：{"amount": amount, "description": description};

• withdraw() function , And desposit() similar , however amount You need to change it to a negative number , If you have any amount happen , Need to put founds Subtract the corresponding amount value , And back to True, Otherwise return to False;

• get_balance() function , return deposit() Functions and withdraw() The result of the function ;

• transfer(amount, another list) function , Judge funds Is it enough , If sufficient , take deposit() Functions and withdraw() Add the function content , And back to True, vice versa ;

• check_funds() function , When amount > balance of the budget category When to return to False, Otherwise return to True;

• Output function , Title line required 30 Characters , Name centered , On both sides “*” character ,description Align left , Maximum 23 position , Superfluous does not show ,amount Align right , Maximum 7 position , Superfluous does not show ,  Add a new line Total Show ;

1.2  create_spend_chart() function

For a print function , Requirements are as follows ：

• Show each category The percentage spent
• The left side shows 0-100 The label of , use 'o' Characters indicate column height , Not an integer , It should be rounded to the nearest 10 It's about
• The horizontal line should be better than the last one bar Two blank lines
• Every category The name of is in the corresponding bar Vertical display below
• The title at the top is "Percentage spent by category"

2 Sample output

category Output ：

*************Food*************
initial deposit        1000.00
groceries               -10.15
restaurant and more foo -15.89
Transfer to Clothing    -50.00
Total: 923.96

create_spend_chart Output ： 

Percentage spent by category
100|          
 90|          
 80|          
 70|          
 60| o        
 50| o        
 40| o        
 30| o        
 20| o  o     
 10| o  o  o  
  0| o  o  o  
    ----------
     F  C  A  
     o  l  u  
     o  o  t  
     d  t  o  
        h     
        i     
        n     
        g     

3 Source code analysis

This question is very lazy , I didn't write it myself , Translated an article written by a big man .

Original link ：FreeCodeCamp----Scientific Computing with Python Projects----Budget-app_m0_43406494 The blog of -CSDN Blog

class Category:
    def __init__(self,name):
        self.name=name
        #  Clear title ledger is a list
        self.ledger=[]
        self.funds=0
    #  Pre deposit 
    def deposit(self,amount,description=''):
        #  The format is required by the title , And description The default value is empty character 
        self.ledger.append({"amount": amount, "description": description})
        self.funds+=amount

    #  Consumption or withdrawal , And deposit The function is the same ,amount It's a negative number 
    #  Premise is funds Is a positive number , Immediate inventory , return True, Otherwise return to False
    def withdraw(self,amount,description=''):
        if self.check_funds(amount):
            self.ledger.append({"amount": -amount, "description": description})
            self.funds-=amount
            return True
        return False

    def get_balance(self):
        return self.funds

    # other Also a list
    def transfer(self,amount,other):
        if not self.check_funds(amount):
            return False
        
        #  Transferred to the other Of list in 
        #  If a transfer occurs ,funds You need to subtract this part of amount, Otherwise, you need to add 
        #  If a transfer occurs ,funds May increase or decrease , Have changed , return True
        self.ledger.append({'amount':-amount,'description':"Transfer to {}".format(other.name)})
        self.funds-=amount
        other.ledger.append({"amount": amount, "description":"Transfer from {}".format(self.name)})
        other.funds+=amount
        return True

    #  According to the requirements ,check_funds Use in withdraw() and transfer() in 
    def check_funds(self,amount):
        if self.funds>=amount:
            return True
        return False

    #  Printing requirements ：
    #  Title Line 30 Characters , Name centered , On both sides “*” character 
    # description Align left , Maximum 23 position , Superfluous does not show 
    # amount Align right , Maximum 7 position , Superfluous does not show 
    #  Add a new line Total Show 
    def __str__(self):
        s=''
        s+=self.name.center(30,'*')+'\n'
        for x in self.ledger:
            if len(x['description'])>23:
                s+=x['description'][0:23]
            else:
                s+=x['description'][0:23].ljust(23)
            s+="{0:.2f}".format(x['amount']).rjust(7)
            s+='\n'
        s+='Total: {}'.format(self.funds)
        return s
            
# It's not round , But to give up a bit ！
# categories is a list
# chart  Show each category The percentage spent 
#  The left side shows 0-100 The label of , use 'o' Characters indicate column height , Not an integer , It should be rounded to the nearest 10 It's about 
#  The horizontal line should be better than the last one bar Two blank lines 
#  Every category The name of is in the corresponding bar Vertical display below 
#  The title at the top is "Percentage spent by category"
def create_spend_chart(categories):
    s="Percentage spent by category\n"
    sum=0
    withdraws={}
    #  The percentage calculation only includes withdrawals
    for x in categories:
        withdraws[x.name]=0
        for y in x.ledger:
            if y['amount']<0:
                withdraws[x.name]+=y['amount']
        withdraws[x.name]=-withdraws[x.name]
    for x in withdraws:
        sum+=withdraws[x]
    for x in withdraws:
        withdraws[x]=int(withdraws[x]/sum*100)
        
    for i in range(100,-10,-10):
        s+=str(i).rjust(3)+'| '
        for x in categories:
            if withdraws[x.name]>=i:
                s+='o  '
            else:
                s+='   '
        s+='\n'
    s+=' '*4+'-'*(1+len(categories)*3)+'\n'

    maxlen=0
    for x in categories:
        if len(x.name)>maxlen:
            maxlen=len(x.name)
    for i in range(maxlen):
        s+=' '*5
        for x in categories:
            if len(x.name)>i:
                s+=x.name[i]+'  '
            else:
                s+=' '*3
        s+='\n'
    return s[0:-1]

if __name__ == "__main__":
    food=Category('food')
    entertainment=Category('entertainment')
    business=Category('Business')
    food.deposit(900, "deposit")
    entertainment.deposit(900, "deposit")
    business.deposit(900, "deposit")
    food.withdraw(105.55)
    entertainment.withdraw(33.40)
    business.withdraw(10.99)
    actual = create_spend_chart([business, food, entertainment])
    print(actual)